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Study the De Morgans theorems and their working using logic circuits


Posted by: seminar class
Created at: Friday 13th of May 2011 05:27:12 AM
Last Edited Or Replied at :Friday 13th of May 2011 05:27:12 AM
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1 = 1
Let A = B = 1; then = = 0 + 0 = 0 Thus, LHS = RHS, hence proved.
Second theorem – it states that the complement of sum is equal to the product of the complements.
Logic equation 
Proof – we shall prove the theorem by showing that LHS & RHS of given equation are equal.
LHS =
Let A = B = 0; then = = = 1
Let A = 0 & B = 1; then = = = 0
Let A = 1 & B = 0; then = = = 0
Let A = B = 1; then = = = 0
RHS =
Let A = B = 0; then = = 1.1 = 1
Let A = 0 & B = 1; then = = 1.0 = 0
Let A = 1 & B = 0; then = = 0.1 = 0
Let A = ..................[:=> Show Contents <=:]



Study the De Morgans theorems and their working using logic circuits


Posted by: seminar class
Created at: Friday 13th of May 2011 05:27:12 AM
Last Edited Or Replied at :Friday 13th of May 2011 05:27:12 AM
wiring diagram 7404 7408 7432 , demorgan s theorem, de morgan s theorem , display theorems through circuits logic, ic 7408 circuit diagram ppt , circuit diagram of demorgan s theorem, circuit diagram for demorgan s theorem proof , display 7432 7408 7404, seminar on demorgan s theorem proof , ic 7404, mathematics truth tables de morgan logic circuits , circuit digram for demorgan theorem, demorgans theorem on with ics , de morgan theorem cirkite diagram, demorgan s theorems , what are demorgan s theorems write them in equation for, de morgans theorems proof , demorgan s theorems proof circuits, circuit to prove de morgan s theorems , de morgan s theorems,
en = = 1+ 0 = 1
Let A = 1 & B = 0; then = = 0 + 1 = 1
Let A = B = 1; then = = 0 + 0 = 0 Thus, LHS = RHS, hence proved.
Second theorem – it states that the complement of sum is equal to the product of the complements.
Logic equation 
Proof – we shall prove the theorem by showing that LHS & RHS of given equation are equal.
LHS =
Let A = B = 0; then = = = 1
Let A = 0 & B = 1; then = = = 0
Let A = 1 & B = 0; then = = = 0
Let A = B = 1; then = = = 0
RHS =
Let A = B = 0; then = = 1.1 = 1
Let A = 0 & B = 1; then = = 1...................[:=> Show Contents <=:]



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