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## Study the De Morgans theorems and their working using logic circuitsPosted by: seminar class Created at: Friday 13th of May 2011 05:27:12 AM Last Edited Or Replied at :Friday 13th of May 2011 05:27:12 AM | wiring diagram 7404 7408 7432 ,
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uct of the complements. Logic equation Proof – we shall prove the theorem by showing that LHS & RHS of given equation are equal. LHS = Let A = B = 0; then = = = 1 Let A = 0 & B = 1; then = = = 0 Let A = 1 & B = 0; then = = = 0 Let A = B = 1; then = = = 0 RHS = Let A = B = 0; then = = 1.1 = 1 Let A = 0 & B = 1; then = = 1.0 = 0 Let A = 1 & B = 0; then = = 0.1 = 0 Let A = B = 1; then = = 0.0 = 0 Thus, LHS = RHS, hence proved. Conclusion – in this way, we have studied the De Morgan’s both theorems and found that
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## Study the De Morgans theorems and their working using logic circuitsPosted by: seminar class Created at: Friday 13th of May 2011 05:27:12 AM Last Edited Or Replied at :Friday 13th of May 2011 05:27:12 AM | wiring diagram 7404 7408 7432 ,
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giving different combinations of logic inputs as shown the respective truth tables. 5) Write the observed truth table of each theorem and hence, write the logic equation. Brief theory –First theorem – it states that the complement of product is equal to the sum of the complements. Logic equation Proof – we shall prove above theorem by showing that LHS & RHS of given equation are equal. LHS = Let A = B = 0; then = = = 1 Let A = 0 & B = 1; then = = = 1 Let A = 1 & B = 0; then = = = 1 Let A = B = 1; then = = = 0 RHS = Let A = B = 0.................. [:=> Show Contents <=:] |

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