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## coordinate geometry maths pptPosted by: Created at: Friday 23rd of November 2012 11:31:03 AM Last Edited Or Replied at :Saturday 24th of November 2012 01:09:13 AM | coordinate geometry maths ,
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## Coordinate Geometry QuestionsPosted by: seminar class Created at: Wednesday 16th of March 2011 05:36:33 AM Last Edited Or Replied at :Thursday 21st of July 2011 12:43:32 AM | coordinate geometry questions ,
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) form a parallelogram. 4. A triangle has vertices A(3, 1), B(-1, -4) and C(-11, 4) (a) Use the gradient formula to prove that the triangle is right angled. (b) Use the distance formula to prove that the triangle is right angled. Answers 1. (a) 2 (b) 43 (c) 94 (d) -2 2. a = 9 Equations of a Straight Line Formula: y – y1 = m(x – x1) or y = mx + b1. Find the equation of a straight line (a) with gradient 4 and y-intercept -1 (b) passing through the origin with gradient -3 (c) with gradient 4 and x-intercept -5 (d) passing through (2, .................. [:=> Show Contents <=:] | |||

## powerpoint presentations on vedic mathematics for class 9thPosted by: Created at: Thursday 04th of October 2012 07:44:18 AM Last Edited Or Replied at :Thursday 04th of October 2012 07:44:18 AM | seminar topics for maths 9th,
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## ppt on coordinate geometry for class 10Posted by: Created at: Sunday 30th of September 2012 11:35:36 AM Last Edited Or Replied at :Monday 01st of October 2012 06:45:56 AM | coordinate geometry ppt class 10,
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## VEDIC MATHEMATICS - VEDIC OR MATHEMATIC A FUZZY NEUTROSOPHIC ANALYSISPosted by: seminar class Created at: Monday 02nd of May 2011 04:43:45 AM Last Edited Or Replied at :Monday 02nd of May 2011 04:43:45 AM | seminar topics vaidik,
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ing and J. Von Negelein, Leipzig,1909-10. But this work of Sri Sankaracharyaji deserves to be regarded as a new Parisista by itself and it is not surprising that the Sutras mentioned herein do not appear in the hitherto known Parisistas. A list of these main 16 Sutras and of their sub-sutras or corollaries is prefixed in the beginning of the text and the style of language also points to their discovery by Sri Swamiji himself. At any rate, it is needless to dwell longer on this point of origin since the vast merit of these rules should be a matter of discovery for each intelligent re.................. [:=> Show Contents <=:] | |||

## Coordinate Geometry QuestionsPosted by: seminar class Created at: Wednesday 16th of March 2011 05:36:33 AM Last Edited Or Replied at :Thursday 21st of July 2011 12:43:32 AM | coordinate geometry questions ,
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oints A(-1, 2), B(1, 5), C(6, 5) and D(4, 2) form a parallelogram. Find the midpoints of the
diagonals AC and BD. What property of a parallelogram does this show? Answers 1. (a) (2, 4) (b) -1, 1) (c) (0, 112 ) 2. (a) a = 9, b = -3 (b) a = 6, b = 1 4. 4. (52 , 72 ) diagonals bisect each other Gradient (slope) F0rmula: m = y2 - y1x2 - x1 1. Find the gradient of the line between (a) (3, 2) and (1, -2) (b) (0, 2) and (3, 6) (c) (1, -4) and (5, 5) (d) (0, 4) and (3, -2) 2. The gradient of a line is -1 and the line passes through (4, 2) and (a, -3). Find the value of a. 3. Use.................. [:=> Show Contents <=:] | |||

## Introduction To DerivativesPosted by: seminar class Created at: Wednesday 16th of February 2011 01:57:43 AM Last Edited Or Replied at :Wednesday 16th of February 2011 01:57:43 AM | introduction to financial mathematics ppt ,
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the trade, the smaller the commission is in percentage terms. Bid-Ask spread – Depending upon whether you are buying or selling an instrument, you will get different prices. If you wish to sell, you will get a “BID” quote, and if you wish to buy you will get an “ASK” quote. The difference between the bid and the ask can vary depending upon whether you are a retail, institutional, or broker trader; it can also vary if you are placing very large trades. In general, however, the bid-ask spread is relatively constant for a given customer/position. The spread is rough.................. [:=> Show Contents <=:] | |||

## Application of Mathematics in Robotics full reportPosted by: project topics Created at: Tuesday 13th of April 2010 12:57:26 AM Last Edited Or Replied at :Tuesday 13th of April 2010 12:57:26 AM | robotics kits ,
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e is: X2 + y2 + z2= r2; The two equations that describe the previous spheres X2 + y2 = 22 (u â€œ x)2 + (v â€œ y)2 + (w â€œ z)2 = 1 Does this system of polynomial equations have real solutions If yes then: How to solve this system of polynomial equations Difficult! Groebner Basis is the tool we can use. The Groebner Basis can help us solve the problem whether the robot can reach a certain point with center at (a, b, c) Solution: In order to find the coordinates of the point we are interested in, we have to find all points the arm can reach and see if this is one.................. [:=> Show Contents <=:] |

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